Question

Question 23

On dividing $p(4p^2-16)$ by $4p(p-2)$, we get
a) $2p+4$
b) $2p-4$
c) $p+2$
d) $p-2$

Answer 1

c) $p+2$

$\to$​​​​​​​We have,
$\frac{p(4p^2-16)}{4p(p-2)}=\frac{p\left[\right(2p{)}^2-4^2]}{4p(p-2)}=\frac{(2p-4)(2p+4)}{4(p-2)}[\because a^2-b^2=(a+b\left)\right(a-b\left)\right]=\frac{2(p-2).2(p+2)}{4(p-2)}=\frac{4(p-2)(p+2)}{4(p-2)}=p+2$