Question

Question 4
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area $1080m^2$? [If required, you can split the tiles in whatever way you want to fill up the corners]

Answer 1

Base of flooring tile = 24 cm = 0.24 m
Corresponding height of a flooring tile = 10 cm = 0.10 m
Now Area of flooring tile = Base $\times$ Altitude = $0.24\times 0.10=0.024m^2$
$\therefore$ Number of tiles required to cover the floor = $\frac{Areaoffloor}{Areaofonetile}$
=$\frac{1080}{0.024}=45000tiles$
Hence 45000 tiles are required to cover the floor.