Question 4(v)
Factorise
$a^{4} - 2 a^{2} b^{2} + b^{4}$

Open in App

Solution

$a^{4} - 2 a^{2} b^{2} + b^{4} = (a^{2})^{2} - 2 (a^{2}) (b^{2}) + (b^{2})^{2} = (a^{2} - b^{2})^{2} = [(a - b) (a + b)]^{2} = (a - b)^{2} (a + b)^{2}$

Suggest Corrections

Similar questions

a^{4} - 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

a^{4} + 2 a^{2} b^{2} + b^{4}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program