wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 6(vi)
Using identities, evaluate:
297×303

Open in App
Solution

297×303=[3003]×[300+3]=(300)2(3)2
[Using identity (ab)(a+b)=a2b2]
=900009=89991

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon