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Question

Using identities, evaluate 297×303

A
8999
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B
899
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C
89991
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D
89990
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Solution

The correct option is B 89991
(297)(303)
=(3003)(300+3)
Using ,
(ab)(a+b)=a2b2 we get,
(300)2(3)2
=900009
=89991

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