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Question

Using an identity, evaluate
297× 303.

A
90001
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B
89998
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C
90008
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D
89991
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Solution

The correct option is D 89991
To evaluate : 297 × 303
297 = 300 - 3
303 = 300+ 3

Using the identity,
(ab)(a+b)=a2b2

Hence,
297×303=(3003)(300+3)=300232=900009=89991

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