Question

Question 8
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface of the system.
$[Assume\pi =\frac{22}{7}]$

Answer 1

Height (h) of cylindrical pipe = length of cylindrical pipe = 28 m

Radius (r) of circular end of pipe
$=\left[\frac{5}{2}\right]=2.5cm=0.025m$

CSA of cylindrical pipe
$=2\pi rh$
$=[2\times \frac{22}{7}\times 0.025\times 28]m^2=4.4m^2$

The area of the radiating surface of the system is CSA of cylindrical pipe $=4.4m^2$.