Question 81 (i)

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$7 a^{2} b c, - 3 a b c^{2}, 3 a^{2} b c, 2 a b c^{2}$

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Solution

We have,
$7 a^{2} b c + (- 3 a b c^{2}) + 3 a^{2} b c + 2 a b c^{2} = 7 a^{2} b c - 3 a b c^{2} + 3 a^{2} b c + 2 a b c^{2}$
$= (7 a^{2} b c + 3 a^{2} b c) + (- 3 a b c^{2} + 2 a b c^{2})$ [grouping like terms]
$= 10 a^{2} b c + (- a b c^{2})$
$= 10 a^{2} b c - a b c^{2}$

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Similar questions

Question 81 (i)

Add :

$7 a^{2} b c, - 3 a b c^{2}, 3 a^{2} b c, 2 a b c^{2}$

p^{4} - 81

p^{4} - 81

Question 95

Solve the following:

Express $\frac{16}{81} a n d \frac{- 16}{81}$ as powers of rational number.

\sqrt[4]{(81)^{- 2}}

\frac{1}{9}

\frac{1}{3}

9

\frac{1}{81}

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