CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 85 (ii)

Expand the following, using suitable identities.

(x2yxy2)2


Open in App
Solution

We have,
(x2yxy2)2=(x2y)2+(xy2)22x2y×xy2
=x4y2+x2y42x3y3 [using the identity, (ab)2=a2+b22ab]


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon