Question 86 (ix)
Using suitable identities, evaluate the following:
105×95
We have, 105×95=(100+5)(100−5) =(100)2−(5)2 [using the identity, (a+b)(a−b)=a2−b2] =10000−25 =9975
Question 86 (ii)
(49)2
Question 86 (xii)
98×103
Question 86 (iii)
(103)2
Question 86 (i)
(52)2