Question 89 (xiii)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$2 x^{3} + 24 x^{2} + 72 x$

Open in App

Solution

We have, $2 x^{3} + 24 x^{2} + 72 x$
$= 2 x (x^{2} + 12 x + 36) = 2 x (x^{2} + 2.6. x + 6^{2})$
$= 2 x (x + 6)^{2} = 2 x (x + 6) (x + 6)$

Suggest Corrections

Similar questions

a^{2} + 2 a b + b^{2} = (a + b)^{2}

9 x^{2} + 24 x + 16

a^{2} + 2 a b + b^{2} = (a + b)^{2}

x^{2} + 6 x + 9

a^{2} + 2 a b + b^{2} = (a + b)^{2}

a^{2} x^{2} + 2 a b x y + b^{2} y^{2}

a^{2} + 2 a b + b^{2} = (a + b)^{2}

a^{2} x^{2} + 2 a b x + b^{2}

Question 92 (xiii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{2}}{8} - \frac{y^{2}}{18}$

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program