Question

Question 97

Match the items of Column I with that of Column II.

$\begin{array}{cccc}& ColumnI& & ColumnII\\ \left(i\right)& Thenumberofcornersofaquadrilaeral& \left(a\right)& =\\ \left(ii\right)& Thevariableintheequation2p+3=5& \left(b\right)& constant\\ \left(iii\right)& Thesolutionoftheequationx+2=3& \left(c\right)& +1\\ \left(iv\right)& solutionoftheequation2p+3=5& \left(d\right)& -1\\ \left(v\right)& Asignusedinanequation& \left(e\right)& p\\ & & \left(f\right)& x\end{array}$

Answer 1

$\begin{array}{cccc}& ColumnI& & ColumnII\\ \left(i\right)& Thenumberofcornersofaquadrilaeral& \left(b\right)& constant\\ \left(ii\right)& Thevariableintheequation2p+3=5& \left(e\right)& p\\ \left(iii\right)& Thesolutionoftheequationx+2=3& \left(c\right)& +1\\ \left(iv\right)& solutionoftheequation2p+3=5& \left(c\right)& +1\\ \left(v\right)& Asignusedinanequation& \left(a\right)& =\end{array}$

(i) The number of corners of a quadrilateral are 4, which is a constant.

(ii) Given, equation is 2p + 3 = 5. A variable is a letter that represents an unknown quantity which can take any value.

$\therefore$ Variable in the given equation = p

(iii) Given, equation is $x+2=3$

Subtracting 2 from both sides of the equation, we get

$x+2-2=3-2$

$\Rightarrow x=1$

(iv) Given, equation is 2p + 3 = 5

Subtracting 3 from both sides of the equation, we get

2p+3-3 = 5 - 3

$\Rightarrow$ 2p = 2

Dividing bpth sides of the equation by 2, we get

$\Rightarrow \frac{2p}{2}=\frac{2}{2}$

$\Rightarrow$ p = 1

(v)An equation has an equal sign (=) between its left hand side and right hand side.