$R - C H_{2} - C H_{2} O H$ can be converted to $R - C H_{2} C H_{2} C O O H$ . The correct sequence of reagents is:

P {B r}_{3}, K C N, H_{3} O^{+}

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P {B r}_{3}, K C N, H_{2}

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K C N, H^{+}

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H C N, P {B r}_{3}, H^{+}

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Solution

The correct option is A $P {B r}_{3}, K C N, H_{3} O^{+}$
$R - C H_{2} - C H_{2} O H$ can be converted to $R - C H_{2} C H_{2} C O O H$ .

The correct sequence of reagents is $P {B r}_{3}, K C N, H_{3} O^{+}$ .

$R - C H_{2} - C H_{2} O H P {B r}_{3} - -- \to R - C H_{2} - C H_{2} - B r K C N - -- \to R - C H_{2} - C H_{2} - C N H_{3} O^{+} - -- \to R - C H_{2} C H_{2} C O O H$

Alcohol is converted to alkyl bromide. Br atom is then substituted with cyano group. Acid hydrolysis of cyano group gives final product (carboxylic acid).

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