What is the final product of the reaction sequence?

$(C H_{3})_{2} C H C O O H (i) L i A l H_{4} ⟶ (i i) H_{2} O P B r_{3} ⟶ K C N ⟶ D M S O H_{2} O, H^{+} ⟶ H e a t$

(C H_{3})_{2} C H C H_{2} C H_{2} N H_{2}

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(C H_{3})_{2} C H C H (B r) C O O H

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(C H_{3})_{2} C = C H - C O O H

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(C H_{3})_{2} C H C H_{2} C O O H

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Solution

The correct option is D $(C H_{3})_{2} C H C H_{2} C O O H$
Reaction:
$(C H_{3})_{2} C H C O O H L i A l H_{4} ⟶ H_{2} O (C H_{3})_{2} C H C H_{2} O H P B r_{3} - -- \to (C H_{3})_{2} C H C H_{2} B r$

$(C H_{3})_{2} C H C H_{2} B r C N^{-} ⟶ (C H_{3})_{2} C H C H_{2} C N H_{2} O ⟶ H^{+} (C H_{3})_{2} C H C H_{2} C O O H$

Option D is correct.

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Similar questions

R - C H_{2} - C H_{2} - O H

R - C H_{2} C H_{2} C O O H

C H \equiv C H \frac{H_{2} O / H g S O_{4}}{H_{2} S O_{4}}

(C H_{3})_{2} C = C H C H_{2} C H_{3} (i) B H_{3} T H F - -------- \to (i i) H_{2} O_{2} / O H^{-}

C H_{2} C l_{2} - ---- \to P C C (i) C H_{3} M g B r - ------- \to (i i) H_{3} O^{+}

In the following sequence of reactions, the product (B) is

$C H_{3} C H O H C N - -- \to (A) H_{2} O - - \to (B)$

C H \equiv C H N a N H_{2} - ---- \to A C H_{3} B r - --- \to B

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