MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Photoelectric Effect

Radiation of ...

Question

Radiation of $λ = 155 n m$ was irradiated to $L i$ (work function $= 5 e v$ ) plate. The stopping potential.

Open in App

Solution

$\begin{matrix} E = \frac{h c}{λ} = \frac{1240}{λ (i n n m)} e v = \frac{1240}{155} . e v E = 80 v E_{T o t a l} = w o r k f u n c t i o n + V_{o} [V_{0} = s t o p p i n g p o t e n t i a l] \Rightarrow 20 v = 50 v + V_{o} ∴ V_{o} = 30 V \end{matrix}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Radiation of

λ = 155 n m

was irradiated on Li (work function - 5 e V) plate.The stopping potential (in V ) is:

Q. Radiation of wavelength 155 nm is incident on Li metal with work function 5.0 eV. The stopping potential will be

Q. When radiation of wavelength

λ

is incident on a metallic surface the stopping potential is 4.8 volts. If the same surface is irradiated with radiation of double the wavelength, then the stopping potential becomes 1.6 volts. Then the threshold wavelength for the surface is

Q. When radiation of

λ = 253.7 nm

strikes the copper plate, the energy required to stop the ejection of electrons from copper plate is

0.24 eV

. Calculate the work function of copper.

Q. Radiation of wavelength 155 nm is incident on Li metal with work function 5.0 eV. The stopping potential will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Photoelectric Effect

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Photoelectric Effect

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon