Question

Radius of a circle is 17 cm. If length of the chord is 30 cm, then find its distance from the centre.

• A. 8

Answer 1

The correct option is A 8

PO is the radius of the circle
$\therefore PO=17cm$.
Given, the length of the chord $PQ=30cm$.
The perpendicular from the centre of the circle to the chord bisects the chord.
$\therefore PM=MQ=15cm$.
Using Pythagoras theorem in $\Delta POM$,
we get,
$P{O}^2=P{M}^2+M{O}^2$
${17}^2={15}^2+M{O}^2$
$\Rightarrow M{O}^2=289-225=64$
$\Rightarrow MO=8cm.$