The radius of a circle is 13 cm and the length of one of its chords is 10 cm- Find the distance of the chord from the centre-A- 13 cmB- 14 cmC- 11 cmD- 12 cm

The correct option is D 12 cm AB = 5 cm OB = Radius = 13 cm ∴ OA = √((OB^2) (AB^2)) OB = 12 cm ...

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Standard IX

Mathematics

Diameter

The radius of...

Question

The radius of a circle is $13$ cm and the length of one of its chords is $10$ cm. Find the shortest distance of the chord from the centre.

11 cm

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12 cm

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13 cm

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14 cm

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Solution

The correct option is D. $12$ cm

$A B = 5$ cm

$O B = R a d i u s = 13$ cm

$∴ O A = \sqrt{({O B}^{2}) - ({A B}^{2})}$
$= \sqrt{13^{2} - 5^{2}}$
$= \sqrt{144}$
$∴ O A = 12$ cm
Hence, the shortest distance of the chord from the centre is $12$ cm.

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The radius of a circle is 13 cm and the length of one of its chords is 10 cm. Find the shortest distance of the chord from the centre.

The correct option is D. 12 cm AB=5 cm OB=Radius=13 cm ∴OA=√(OB2)−(AB2)=√132−52=√144∴OA=12 cmHence, the shortest distance of the chord from the centre is 12 cm.

The radius of a circle is $13$ cm and the length of one of its chords is $10$ cm. Find the shortest distance of the chord from the centre.

The correct option is D. $12$ cm

$A B = 5$ cm

$O B = R a d i u s = 13$ cm

$∴ O A = \sqrt{({O B}^{2}) - ({A B}^{2})}$
$= \sqrt{13^{2} - 5^{2}}$
$= \sqrt{144}$
$∴ O A = 12$ cm
Hence, the shortest distance of the chord from the centre is $12$ cm.