Question

The radius of a circle is $10cm$ and the length of one of its chords is $12cm$ then the distance of the chord from the centre is

• A. $6cm$
• B. $12cm$
• C. $10cm$
• D. $8cm$

Answer 1

The correct option is D $8cm$

R.E.F image

Given OA=OB=10CM

AB=12CM

In $△$ OAC

$(OA{)}^2=(O{C}^2)+(AC{)}^2$

$(10{)}^2=(OC{)}^2+(OC{)}^2+(6{)}^2$

$(OC{)}^2=100-36$

$(OC{)}^2=64$

[OC=8CM]

$\therefore$[ length of OC=8cm.]