Radius of curvature of a convex mirror used in automobile is $10 c m$ . A car is coming behind it at a constant distance of $17.5 m$ . Calculate the position of the image.

17.5 c m

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0.20 c m

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5 c m

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20 c m

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Solution

The correct option is C $5 c m$
Given:
$R = 10, f = \frac{10}{2} = 5, u = - 17.5 m = - 1750 c m$
$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$
$\frac{1}{5} = \frac{1}{v} + \frac{1}{(- 1750)}$
$\frac{1}{v} = \frac{1}{5} + \frac{1}{1750}$
$= \frac{1}{5} + \frac{1}{1750}$
$= \frac{1750 + 5}{5 \times 1750} = \frac{1755}{8750} = 0.20$
Therefore, the position of the image, $v = \frac{1}{0.20} = 5 c m$

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Radius of curvature of a convex mirror used in automobile is 10cm. A car is coming behind it at a constant distance of 17.5m. Calculate the position of the image.

The correct option is C 5cmGiven:R=10, f=102=5,u=−17.5m=−1750cm 1f=1v+1u15=1v+1(−1750)1v=15+11750=15+11750=1750+55×1750=17558750=0.20Therefore, the position of the image, v=10.20=5cm

Radius of curvature of a convex mirror used in automobile is $10 c m$ . A car is coming behind it at a constant distance of $17.5 m$ . Calculate the position of the image.