Radius of the circle touching the line $3 x + 4 y - 14 = 0, 6 x + 8 y + 7 = 0 i s : -$

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\frac{7}{2}

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\frac{7}{4}

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\frac{7}{6}

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Solution

The correct option is C $\frac{7}{4}$
$3 x + 4 y - 14 = 0$
$6 x + 8 y + 7 = 0$
$= 3 x + 4 y + \frac{7}{2}$
find distance betn line & $△_{0} / 2$
$= \frac{\frac{7}{2} - (- 14)}{\sqrt{3^{3} + 4^{2}}}$
$\frac{\frac{7}{2} + 14}{5} = \frac{35}{10} \times 2$
$= \frac{35}{20} 2$
$= \frac{7}{4}$

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Similar questions

3 x + 4 y - 14 = 0

6 x + 8 y + 7 = 0

3 x - 4 y = 4

6 x - 8 y - 7 = 0

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

If the lines $3 x - 4 y + 4 = 0$ amd $6 x - 8 y - 7 = 0$ are tangents to a circle, find the radius of the circle.

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

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