Raghu walks around a park whose dimensions are given in the figure. How much distance will he cover in two rounds?

328 m

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298 m

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228 m

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656 m

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Solution

The correct option is D 656 m
The length of the boundary of a closed planar figure is called its perimeter.

One round around the park represents its perimeter.

Raghu walks two times around the park.
So, the total distance covered
$= 2 \times$ Perimeter of the park
$= 2 \times (66 + 75 + 102 + 85) m$
$= (2 \times 328) m = 656 m$

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Raghu walks around a park whose dimensions are given in the figure. How much distance will he cover in two rounds?

The correct option is D 656 mThe length of the boundary of a closed planar figure is called its perimeter. One round around the park represents its perimeter. Raghu walks two times around the park. So, the total distance covered =2× Perimeter of the park =2×(66+75+102+85) m =(2×328) m=656 m