Rahul went to pay the bill. He came to know that the price of a pant is Rs.300 and price of the shirt are Rs. 250. What is the amount paid by Rahul if the algebraic expression for the total price was (3x + 4y), where x is the price of a pant and y is the price of a shirt? [3 MARKS]

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Solution

Steps: 2 Marks
Answer: 1 Mark

It is given that; total price of the clothes is equal to $3 x + 4 y .$
x is the price of the pant, $x = R s . 300$
y is the price of the shirt, $y = R s . 250$
Therefore, the total amount $= 3 \times 300 + 4 \times 250 = 900 + 1000 = R s . 1900$

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Rahul went to pay the bill. He came to know that the price of a pant is Rs.300 and price of the shirt are Rs. 250. What is the amount paid by Rahul if the algebraic expression for the total price was (3x + 4y), where x is the price of a pant and y is the price of a shirt? [3 MARKS]

Steps: 2 Marks Answer: 1 Mark It is given that; total price of the clothes is equal to 3x+4y. x is the price of the pant, x=Rs.300 y is the price of the shirt, y=Rs.250 Therefore, the total amount =3×300+4×250=900+1000=Rs.1900

Steps: 2 Marks
Answer: 1 Mark

It is given that; total price of the clothes is equal to $3 x + 4 y .$
x is the price of the pant, $x = R s . 300$
y is the price of the shirt, $y = R s . 250$
Therefore, the total amount $= 3 \times 300 + 4 \times 250 = 900 + 1000 = R s . 1900$