Question

Rain is falling vertically with a speed of $30m{s}^{-1}$. A woman rides a bicyle with a speed of $12m{s}^{-1}$ in east to west direction. What is the direction in which she should hold her umbrella?

• A. At an angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the east.
• B. At angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the west.
• C. At angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the east.
• D. At angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the west.

Answer 1

The correct option is D At angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the west.


In figure, $\overrightarrow{v_r}$ represents the velocity of rain and $\overrightarrow{v_b}$, the velocity of the bicyle the woman is riding. To protect herself from rain, the woman should hold her umbrella in the direction of relative velocity of rain with respect to the bicycle, $\overrightarrow{v_{rb}}.$
from figure,
$Tan\theta =\frac{v_b}{v_r}=\frac{12}{30}=\frac{2}{5}$ or $\theta =ta{n}^{-1}\left(\frac{2}{5}\right)$
Therefore, the woman should hold her umbrella at an angle of $ta{n}^{-1}\left(\frac{2}{5}\right)$ with the vertical towards the west.