Rajan got married 8 years ago. His present age is $\frac{6}{5}$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The present age of Rajan's sister is

32

years

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36

years

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38

years

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34

years

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Solution

The correct option is B $38$ years
$x$ be Rajan's age during the marriage
$x + 8$ present age
given $(x + 8) = \frac{6}{5} x$
8= $(\frac{6}{5} - 1) x$ 8= $\frac{x}{5} x = 40$
$y$ be rajani's sisters age during rajani's marriage
given $y = x - 10$
$y = 30$
present age of sister $= y + 8 = 38$

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Rajan got married 8 years ago. His present age is $\frac{6}{5}$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The age of Rajan's sister is:

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Rajan got married 8 years ago. His present age is 65 times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The present age of Rajan's sister is

The correct option is B 38 yearsx be Rajan's age during the marriagex+8 present agegiven (x+8)=65x8=(65−1)x 8=x5x=40y be rajani's sisters age during rajani's marriage given y=x−10y=30 present age of sister =y+8=38

Rajan got married 8 years ago. His present age is $\frac{6}{5}$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The present age of Rajan's sister is

The correct option is B $38$ years
$x$ be Rajan's age during the marriage
$x + 8$ present age
given $(x + 8) = \frac{6}{5} x$
8= $(\frac{6}{5} - 1) x$ 8= $\frac{x}{5} x = 40$
$y$ be rajani's sisters age during rajani's marriage
given $y = x - 10$
$y = 30$
present age of sister $= y + 8 = 38$