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Standard VIII

Mathematics

Relation for Inverse Proportion

Rakesh can do...

Question

Rakesh can do a piece of work in 20 days. How much work can he do in 4 days?

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Solution

$It is given that Rakesh can do a piece of work in 20 days . ∴ Rakesh' s 1 day's work = \frac{1}{20} ∴ Rakesh' s work for 4 days = \frac{4}{20} = \frac{1}{5} Thus, he can do \frac{1}{5} th of the work in 4 days .$

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Rakesh can do a piece of work in 20 days. How much work can he do in 4 days?

It is given that Rakesh can do a piece of work in 20 days.∴ Rakesh's 1 day's work=120∴ Rakesh's work for 4 days=420=15Thus, he can do 15th of the work in 4 days.

$It is given that Rakesh can do a piece of work in 20 days . ∴ Rakesh' s 1 day's work = \frac{1}{20} ∴ Rakesh' s work for 4 days = \frac{4}{20} = \frac{1}{5} Thus, he can do \frac{1}{5} th of the work in 4 days .$