A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in how many days ?

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Solution

B's 9 day's work = $(\frac{1}{12} \times 9) = \frac{3}{4}$

Remaining work = $1 - \frac{3}{4} = \frac{1}{4}$

$\frac{1}{20}$ work is finished by A in 1 day.

$\frac{1}{4}$ work is finished by A in $(20 \times \frac{1}{4}) = 5 d a y s$

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Similar questions

$A$ can do a piece of work in $20$ days which $B$ alone can do in $12$ days. Both started working together, $B$ worked at it for $9$ days. $A$ can finish the remaining work in

(a) $3$ days

(b) $5$ days

(d) $11$ days

Q. Tick (✓) the correct answer:
A can do a piece of work in 20 days which B alone can do in 12 days. B worked at it for 9 days. A can finish the remaining work in
(a) 3 days
(b) 5 days
(c) 7 days
(d) 11 days

A

alone can do a piece of work in

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days and

B

alone can do the same work in

12

days.

A

works alone for the first four days. In how many days will

A

and

B

together finishing the remaining work?

Q. X can do a piece of work in 25 days and Y can finish it in 20 days. They work together for 5 days and then X leaves. In how many days will Y finish the remaining work ?

James can do a piece of work in 25 days and Kishan can finish it in 20 days. They work together for 5 days and then James leaves. In how many days will Kishan finish the remaining work?

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A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in how many days ?

B's 9 day's work = (112×9)=34Remaining work = 1−34=14120 work is finished by A in 1 day.14 work is finished by A in (20×14)=5 days

B's 9 day's work = $(\frac{1}{12} \times 9) = \frac{3}{4}$

Remaining work = $1 - \frac{3}{4} = \frac{1}{4}$

$\frac{1}{20}$ work is finished by A in 1 day.

$\frac{1}{4}$ work is finished by A in $(20 \times \frac{1}{4}) = 5 d a y s$