Ram soaked 8g of raisins in water and after 4 hours found that their mass has been 12g . Determine the percentage of water absorbed by raisins.

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Solution

Percentage of water soaked = Final weight - Initial weight / Initial weight X 100

= 12 - 8 / 8 X 100

= 0.005

mass of dry raisins=8g=x

mass of wet raisins=12g=y

y-x/x= 4/8 =1/2 = 0.5%

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Ram soaked 8g of raisins in water and after 4 hours found that their mass has been 12g . Determine the percentage of water absorbed by raisins.

Percentage of water soaked = Final weight - Initial weight / Initial weight X 100 = 12 - 8 / 8 X 100 = 0.005 mass of dry raisins=8g=x mass of wet raisins=12g=y y-x/x= 4/8 =1/2 = 0.5%

Percentage of water soaked = Final weight - Initial weight / Initial weight X 100

= 12 - 8 / 8 X 100

= 0.005

mass of dry raisins=8g=x

mass of wet raisins=12g=y

y-x/x= 4/8 =1/2 = 0.5%