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Question

Ramu moves along the periphery of a square field of side 10 m. He completes travelling one side in 40 s. What will be the magnitude of distance and displacement at the end of 2 minutes and 20 seconds ?


A

35 m, 35 m

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B

35 m, 5 m

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C

25 m, 10 m

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D

35 m, 10 m

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Solution

The correct option is B

35 m, 5 m


Distance covered = Length of one side of square field = 10 m.
Time taken to cover one side of the field, t = 40 s.
We know, speed = distancetime.
speed, s = 1040 = 0.25 ms1.
Now we have to find the magnitude of distance and displacement at the end of 2 minutes and 20 seconds.
Here time taken, t = [2×60]+20=140 s.
Distance covered = speed×time = 0.25×140 = 35 m.
In travelling 35 m around a square of perimeter 40 m, Ramu is 5 m off from his initial position.
Therefore, Ramu's displacement is 5 m.

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