Ramu moves along the periphery of a square field of side 10 m. He completes travelling one side in 40 s, the magnitude of distance at the end of 2 minutes and 20 seconds is
A
35 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
25 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 35 m Distance covered=Length of one side of square field = 10 m Time taken to cover one side of the field, t = 40 s We know, speed = distancetime ⇒speed, s = 1040= 0.25ms−1 Now we have to find the magnitude of distance at the end of 2 minutes and 20 seconds. Here time taken, t = [2×60] + 20 = 140 s ∴Distance covered = speed×time = 0.25×140 = 35 m