Range of $14, 12, 17, 18, 16$ and $x$ is $20$ . Find $x$ $(x > 0)$

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Cannot be determined

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $32$
Let $x$ be the highest no. and here lowest no. is $12$
Since, Range $=$ Highest value $-$ Lowest value
$∴ 20 = x - 12$
$∴ x = 32$
$∴$ Option $C$ is correct.

Suggest Corrections

Similar questions

14, 12, 17, 18, 16, x

20

x > 0

x

3 x^{2} - 22 x + 7 = 0

y^{2} - 20 y + 91 = 0

6 x^{2} + 13 x - 28 = 0

3 y^{2} - 25 y + 28 = 0

I . x^{2} - 20 x + 91 = 0 I I . y^{2} - 32 y + 247 = 0

An infinite number of tangents can be drawn from (1, 2) to the circle $x^{2} + y^{2} - 2 x - 4 y + λ = 0,$ then $λ =$

Join BYJU'S Learning Program