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B
(−1,1)
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C
[−1,1]
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D
(0,1)
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Solution
The correct option is B(−1,1) 2x+2−x is always > 0 i,e., domain is R y=2x−2−x2x+2−x=22x−122x+1 ⇒1+y1−y=2.22x2 (Componendo Dividendo) =22x>0 ⇒1+y1−y>0 i.e., (1+y)21−y2>0 ⇒1−y2>0⇒−1<y<1