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Question

Range of the function y=2x2x2x+2x is

A
R
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B
(1,1)
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C
[1,1]
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D
(0,1)
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Solution

The correct option is B (1,1)
2x+2x is always > 0 i,e., domain is R
y=2x2x2x+2x=22x122x+1
1+y1y=2.22x2 (Componendo Dividendo)
=22x>0
1+y1y>0 i.e., (1+y)21y2>0
1y2>0 1<y<1

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