wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Rate of diffusion of LPG (mixture of n-butane and propane) is 1.25 times faster than that of SO3. Hence, mole fraction of n-butane in LPG is

A
0.75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.87
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.51
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.51
rLPGrSO3=MSO3MLPG=1.25
80MLPG=1.25
MLPG=80(1.25)2=51.2
Mean molar mass of mixture of two gases with mole fractions χ1 and χ2 is
=M1χ1+M2χ2
Gas (1) is n-butane and gas (2) is propane.
Thus, 51.2=58χ1+44(1χ1)
χ1=0.51
Hence, mole fraction of n-butane = 0.51

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon