Question

Rate of formation of $S{O}_3$ in the following reaction $2S{O}_2+O_2\to 2S{O}_3$ is $100$ $kg.mi{n}^{-1}$. Hence rate of disapperance of $S{O}_2$ will be:

• A. $100kgmi{n}^{-1}$
• B. $80kgmi{n}^{-1}$
• C. $64kgmi{n}^{-1}$
• D. $32kgmi{n}^{-1}$

Answer 1

Answer: (B)

$80kgmi{n}^{-1}$

(B) 80 kg/ min

$2S{O}_2+O_2\to 2S{O}_3$

$\frac{1}{2}\frac{d\left[S{O}_2\right]}{dt}=\frac{1}{2}\frac{d\left[S{O}_3\right]}{dt}$

$[\because n=\frac{wt}{G.mwt}]$

$\frac{x}{64}=\frac{100}{80}$

$x=80kg/min$