Question

Ravi purchased $5\mathrm{kg}400\mathrm{g}$ rice, $2\mathrm{kg}20\mathrm{g}$ sugar and $10\mathrm{kg}850\mathrm{g}$ flour. Find the total weight of his purchases.

Answer 1

We know that

$1\mathrm{kg}=1000\mathrm{g}$

Given

Weight of rice $=5\mathrm{kg}400\mathrm{g}=5\mathrm{kg}+\frac{400}{1000}\mathrm{kg}=5.400\mathrm{kg}$

Weight of sugar $=2\mathrm{kg}20\mathrm{g}=2\mathrm{kg}+\frac{20}{1000}\mathrm{kg}=2.020\mathrm{kg}$

Weight of flour $=10\mathrm{kg}850\mathrm{g}=10\mathrm{kg}+\frac{850}{1000}\mathrm{kg}=10.850\mathrm{kg}$

The total weight of his purchases is

$5.400+2.020+10.850=18.270\mathrm{kg}$

Hence the total weight of his purchases is $18.270\mathrm{kg}$