Question

Reaction :
$Ba{O}_2\left(s\right)\rightleftharpoons BaO\left(s\right)+O_2\left(g\right)\Delta H=+ve$
In equilibrium condition, pressure of $O_2$ depends on :

• A. Mass of $Ba{O}_2$
• B. Mass of $BaO$
• C. Increasing temperature at equilibrium.
• D. (a) and (b) above.

Answer 1

The correct option is C Increasing temperature at equilibrium.

Since, $\Delta H$ is positive for this reaction. So, it is endothermic in nature. By applying Le Chatelier's principle, On increasing the temperature, the reaction proceeds in a forward direction. So, the pressure of $O_2$ will increase on increasing the temperature at equilibrium.