Question

Reaction $Ba{O}_2\left(s\right)\rightleftharpoons BaO\left(s\right)+O_2\left(g\right)$ ; H = + ve. In equilibrium condition. Pressure of O${}_2$ is depend on:

• A. increase mass of BaO${}_2$
• B. increase mass of BaO
• C. increase temperature on equilibrium
• D. increase mass of BaO${}_2$ and BaO both

Answer 1

The correct option is C increase temperature on equilibrium

The given reaction is:-

${BaO}_2\left(s\right)\rightleftharpoons BaO\left(s\right)+O_2\left(g\right);H=+ive$

Since $H$ is $+ive$ for this reaction. So, it is endothermic in nature. On increasing the temperature, by applying Le Chatelier's principle, we can see that the reaction proceeds in a forward direction on increasing temperature. So, the pressure of $O_2$ will increase on increasing the temperature at equilibrium.