Reaction of chromium metal powder with sulphuric acid results in the formation of :

C r_{2} O_{4}

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chromic acid.

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chromous sulphate.

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none of the above.

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Solution

The correct option is D chromous sulphate.
$C r + H_{2} S O_{4} \to C r S O_{4} + H_{2}$
$4 C r S O_{4} + 2 H_{2} S O_{4} + O_{2} \to 2 C r_{2} (S O_{4})_{3} + 2 H_{2} O$
So, chromic sulphate ( $C r_{2} (S O_{4})_{3}$ ) is the product.

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