Reaction of sodium ethoxide and ethyl iodide will give:

ether

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ethyl alcohol

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acetaldehyde

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acetic acid

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Solution

The correct option is B ether
$C_{2} H_{5} - . . O N a + C_{2} H_{5} I \to C_{2} H_{5} e t h e r - O - C_{2} H_{5} + N a I$ .

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