Question

Rebecca has two different square cards. Card A of area $50c{m}^2$ and card B of area $72c{m}^2$. She wants to make a rectangular card whose length is equal to side length of card A and breadth is equal to side length of card B. Area of the rectangular card is $c{m}^2$

Answer 1

Given that Rbecca has two square shaped cards.
Card A of area $50c{m}^2$
Card B of area$72c{m}^2$
Side length of square-shaped card A $=\sqrt{50}=\sqrt{5\times 5\times 2}=5\sqrt{2}\text{cm}$

Side length of square-shaped card B $=\sqrt{72}=\sqrt{2\times 6\times 6}=6\sqrt{2}\text{cm}$

Area of the rectangular shaped card is
$=\text{Side length of card A}\times \text{side length of card B}=5\sqrt{2}\times 6\sqrt{2}=60c{m}^2$