Question 77

Rectangle MNOP is made up of four congruent rectangles. If the area of one of the rectangles is $8 m^{2}$ and breadth is 2 m, then find the perimeter of MNOP?

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Solution

We have, area of one rectangle $= 8 m^{2}$
and breadth = 2 m
We know that,
Area of rectangle $= l \times b$
$\Rightarrow l \times b = 8$
$\Rightarrow l \times 2 = 8 \Rightarrow l = 4 m$
Now, we have to find the perimeter of MNOP, which contians four congruent rectangles. it means they have same length and breadth.
$∴$ Perimeter of rectangle MNOP = MN + NC + CD + DO + PO + PF + FA + MA
= 4 + 2 + 4 + 2 + 4 + 2 + 4 + 2
= 24 m
Hence, the perimeter of MNOP is 24 m.

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Question 77 Rectangle MNOP is made up of four congruent rectangles. If the area of one of the rectangles is 8 m2 and breadth is 2 m, then find the perimeter of MNOP?

Question 77

Rectangle MNOP is made up of four congruent rectangles. If the area of one of the rectangles is $8 m^{2}$ and breadth is 2 m, then find the perimeter of MNOP?