Reduce the following equation on into intercept form and find there intercepts on the axis
$3 x + 2 y - 12 = 0$

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Solution

$3 x + 2 y - 12$
$⟹ \frac{3 x}{12} + \frac{2 y}{12} = 1$
$⟹ \frac{x}{4} + \frac{y}{6} = 1$

$x$ intercept $= 4$
$y$ intercept $= 6$

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