Question

Reduce the following fractions to their lowest forms.
a. $\frac{36}{144}$

b. $\frac{65}{117}$

c. $\frac{180}{120}$

• A. $a=\frac{1}{4},b=\frac{65}{117},c=\frac{2}{3}$
• B. $a=\frac{1}{4},b=\frac{5}{9},c=\frac{3}{2}$
• C. $a=\frac{1}{4},b=\frac{65}{117},c=\frac{3}{2}$
  
• D. $a=\frac{3}{4},b=\frac{65}{117},c=\frac{2}{3}$
  

Answer 1

The correct option is B $a=\frac{1}{4},b=\frac{5}{9},c=\frac{3}{2}$

$(a.)\left(\frac{36}{144}\right)=\left(\frac{3}{12}\right)=\left(\frac{1}{4}\right)(b.)\left(\frac{65}{117}\right)=\left(\frac{13\cdot 5}{13\cdot 9}\right)=\left(\frac{5}{9}\right)(c.)\left(\frac{180}{120}\right)=\left(\frac{60\cdot 3}{60\cdot 2}\right)=\left(\frac{3}{2}\right)$