Question

Reduce the given fraction to their lowest term.
i. $\frac{18}{81}$

Answer 1

Given, fraction is $\frac{18}{81}$.

$18=2\times 3\times 3$

$81=3\times 3\times 3\times 3$

$\therefore$ H.C.F of 18 and 81 is $3\times 3=9$.

$\frac{18÷9}{81÷9}=\frac{2}{9}$

Hence, $\frac{2}{9}$ is the lowest term.