Question

Reduce the given fraction to their lowest term.
i. $\frac{40}{120}$

Answer 1

Given, fraction is $\frac{40}{120}$.

$40=2\times 2\times 2\times 5$

$120=2\times 2\times 2\times 5\times 3$

$\therefore$ H.C.F of 40 and 120 is $2\times 2\times 2\times 5=40$.

$\frac{40÷40}{120÷40}=\frac{1}{3}$

Hence, $\frac{1}{3}$ is the lowest term.