Question

Reduced form of the given algebraic expression : $\frac{b^2-5b}{3b-4a}\times \frac{9b^2-16a^2}{b^2-25}÷\frac{3b^2+4ab}{ab+5a}$ is _____.

Answer 1

$\frac{b^2-5b}{3b-4a}\times \frac{9b^2-16a^2}{b^2-25}÷\frac{3b^2+4ab}{ab+5a}$
$=\frac{b^2-5b}{3b-4a}\times \frac{9b^2-16a^2}{b^2-25}\times \frac{ab+5a}{3b^2+4ab}$

$=\frac{b(b-5)}{(3b-4a)}\times \frac{(3b+4a)(3b-4a)}{(b+5)(b-5)}\times \frac{a(b+5)}{b(3+4a)}$

$=a$