Reena and Ruchira borrowed Rs. 60,000 and Rs. 50,000 respectively for a period of 3 years. Reena paid simple interset at the rate of 10% per annum, while Ruchira paid compound interest at the rate of 10% compounded annually. Who paid more interest and by how much?
Principal amount P=Rs. 60,000
Time (T)=3 years
Rate of interest (R)=10% per annum
Simple interest S.I=PRT100
=Rs. 60000×10×3100
=Rs. 18000
Case 2: [For Ruchira]
Principal amount =Rs. 50,000
Time (T)=3 years
Rate of interest (R)=10% compounded annually.
So, n=3
Now, The total amount on compounded annually is,
A=P(1+R100)n
⇒A=Rs. 50,000(1+10100)3
⇒A=Rs. 50,000(1+110)3
⇒A=Rs. 50,000×(1110)3
⇒A=Rs. 50,000×1110×1110×1110
⇒A=Rs. 50×1331
⇒A=Rs. 66550
Compound interest (C.I)=A−P
⇒(C.I)=Rs. 66550−Rs. 50,000
⇒(C.I)=Rs. 16,550
Therefore, Reena paid more.
More amount =Rs. 18000−Rs. 16,550=Rs. 1450