Question

Reenu's father is thrice as old as Reenu. After $12$ years he will be just twice his daughter. Find their present ages.

Answer 1

Let Reenu's present age be $x$.

Then, her father's present age will be $3x$.

Reenu's age after $12$ years $=x+12$

Her father's age after 12 years $=3x+12$

It is given that, after $12$ years, Reenu's father will be twice of Reenu.

$\Rightarrow 3x+12=2(x+12)$

$\Rightarrow 3x+12=2x+24$

$\Rightarrow 3x-2x=24-12$

$\Rightarrow x=12$

Therefore,Reenu's present age $=12$ years

Reenu's father's age $=3\times 12=36$ years