Refer the above figure and find the value of n

The correct option is C √( 5 )/ 2 n #160; = hypotenuse adjacent = 2√(5) 4 = √(5) 2 ...

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Standard X

Mathematics

Sum of N Terms of an AP

Refer the abo...

Question

Refer the above figure and find the value of $sec n$

\sqrt{5}

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2 \sqrt{5}

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\frac{\sqrt{5}}{2}

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\frac{\sqrt{5}}{5}

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\frac{2 \sqrt{5}}{5}

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Solution

The correct option is C $\frac{\sqrt{5}}{2}$
$sec n = \frac{h y p o t e n u s e}{a d j a c e n t} = \frac{2 \sqrt{5}}{4} = \frac{\sqrt{5}}{2}$

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Similar questions

x = \frac{\sqrt{5} - 2}{\sqrt{5} + 2}

and

y = \frac{\sqrt{5} + 2}{\sqrt{5} - 2}

Find the value of

x y

Let N = $\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} \cdot \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ then the value of ${log}_{2} N$ =

Q. Let

N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}

, then the value of

{log}_{2} N =

If N = [{√(√5+2) + √(√5-2)}/√(√5+1)] - √(√5+1), then find the value of N. (last answer that you gave was wrong).

x = \frac{\sqrt{5} - 2}{\sqrt{5} + 2}

and

y = \frac{\sqrt{5} + 2}{\sqrt{5} - 2}

Find the value of

x^{2} + y^{2} + x y

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Refer the above figure and find the value of secn

The correct option is C √52secn=hypotenuseadjacent=2√54=√52

Refer the above figure and find the value of $sec n$

The correct option is C $\frac{\sqrt{5}}{2}$
$sec n = \frac{h y p o t e n u s e}{a d j a c e n t} = \frac{2 \sqrt{5}}{4} = \frac{\sqrt{5}}{2}$