Refer to fig. Let $Δ U_{1}$ and $Δ U_{2}$ , be the changes in internal energy of the system in the processes A and B then

Δ U_{1} > Δ U_{2}

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Δ U_{1} = Δ U_{2}

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Δ U_{1} < Δ U_{2}

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Δ U_{1} \neq Δ U_{2}

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Solution

The correct option is B $Δ U_{1} = Δ U_{2}$
The correct answer is option(B).
As we can see from the graph, its a cyclic process, the system starts and returns to the same thermodynamic state.
Because the process is cyclic, there is no change in internal energy after each cycle.

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Q. Refer to figure. Let ∆U₁ and ∆U₂ be the changes in internal energy of the system in the process A and B. Then
(a) ∆U₁ > ∆U₂
(b) ∆U₁ = ∆U₂
(c) ∆U₁ < ∆U₂
(d) ∆U₁ ≠ ∆U₂.

A gas is expanded from volume $V_{0} t o 2 V_{0}$ under three different processes, as shown in the figure. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let $Δ U_{1}, Δ U_{2}$ and $Δ U_{3}$ be the change in the internal energy of the gas in these three processes, then: